Calculator #17

Isolating Transformer Load

Match a series isolating transformer rating to the fixture load it serves, with loading percentage, secondary voltage and losses.

About this calculator

Each fixture on a series circuit is fed through an isolating transformer that isolates the lamp circuit from the high-voltage series circuit and keeps the series circuit closed if the lamp fails. A transformer that is too small overheats, and one that is too large runs lightly loaded, with lower efficiency and a poorer power factor that add to the circuit load. This tool finds the smallest standard size that carries the load and shows how every size compares.

Quick start

Load on One Transformer

Rule note

Most fixtures have their own transformer. Some, such as certain stop bar arrangements, share one.

Rule note

Power at the operating current, from the manufacturer's data sheet. At a lower brightness step the lamp draws less than at full brightness, so enter the power at that current.

Rule note

Anything else on the same secondary, such as a heater or a monitoring device. Leave 0 if none.

Rule note

Normally 6.6 A. For a 20/6.6 A transformer enter 6.6 A (the secondary), not the 20 A primary current, because the secondary voltage is worked out from this value.

Rule note

Current at which the nominal VA rating applies, normally 6.6 A. Some 300 W and 500 W types have a 20 A secondary. At a lower brightness-step current the usable capacity is the rating × (operating ÷ rated current).

Rule note

1.00 for plain lamps. For LED fixtures, enter the driver's power factor.

Rule note

Planning assumption for the primary-side load. Efficiency falls at light loading, so use manufacturer data, or see Calculator #18.

Selection Rules & Circuit

Rule note

Your project's own loading window, not a standard value.

Rule note

Nominal sizes, treated as VA. Confirm against your transformer data sheet.

Rule note

Used for the circuit totals. Set 0 to skip.

FAQ

Isolating Transformer Load Calculator: Frequently Asked Questions

Quick answers on matching a series isolating transformer rating to the fixture load it serves.

What does the Isolating Transformer Load calculator do?

It matches a series isolating transformer rating to the fixture load it serves. It finds the smallest standard size that carries the load and shows how every size compares, with loading percentage, secondary voltage and losses. A transformer that is too small overheats, and one that is too large runs lightly loaded, with lower efficiency and a poorer power factor that add to the circuit load.

How is the secondary load calculated?

Add the fixtures and any extra load on the secondary, then convert to apparent power with the fixture power factor. The real load is the number of fixtures times the watts per fixture plus the extra load, and the apparent load is that real load divided by the power factor. Use 1.00 for plain lamps, and the driver's power factor for LED fixtures.

How is the transformer size chosen?

Each standard size is compared as a percentage of its nominal rating, treated as VA at the rated secondary current of 6.6 A. At a lower operating current the usable capacity scales down in proportion. The recommended size is the smallest one at or below your maximum loading. If that size is below your preferred minimum, the tool says so, because a lightly loaded transformer wastes capacity. The loading window is your project's own, not a standard value.

Which transformer sizes are offered?

The sizes are 10/15 W, 20/25 W and 30/45 W (dual-rated, treated as 15, 25 and 45 VA), then 65 W, 100 W, 150 W, 200 W, 300 W and 500 W, the ratings listed in FAA AC 150/5345-47C. They are nominal sizes treated as VA, so confirm them against your transformer data sheet.

What secondary current do I enter for a 20/6.6 A transformer?

Enter 6.6 A, which is the secondary, and not the 20 A primary current. The secondary voltage is worked out from this value. The rated secondary current is the current at which the nominal VA rating applies, normally 6.6 A. Some 300 W and 500 W types have a 20 A secondary, and for those you enter 20 A.

How are the secondary voltage and primary load worked out?

The secondary voltage is the apparent power divided by the secondary (lamp) current, which is 6.6 A for most types. The primary real load is the secondary real load divided by the efficiency, and the transformer loss is the difference. The primary load is real power and feeds the circuit load calculation. For CCR kVA the transformer's magnetising current also counts, and FAA AC 150/5345-47C allows a power factor as low as 0.95 at rated load, so use Calculators #13 and #16 for kVA. Efficiency is a planning assumption, so use manufacturer data; the AC sets minimums of 70 to 90 percent depending on size.

Can you give a worked example?

One 45 W fixture with a power factor of 1.00 gives 45 VA, and at 6.6 A the secondary voltage is 6.82 V. A 30/45 W transformer is loaded 100 percent, at the limit, and a 65 W transformer is loaded 69 percent, so the recommended size is 30/45 W. At 90 percent efficiency the primary load is 50 W with 5 W of loss, and 100 transformers give 5.00 kW of primary load.

What does the tool not do?

It does not model transformer efficiency curves, magnetising current, secondary open-circuit voltage or lamp-out behaviour, and the sizes offered are nominal. A fixture with a switching driver can behave differently from a plain lamp, so use the manufacturer's guidance for the pairing. For efficiency across loading use Calculator #18, and for a multi-fixture order list use Calculator #49. Final selection shall be verified against the isolating transformer and fixture manufacturers' data.

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